Question

HELP ASAP!!!

The line (y-1)=(2/3)(x+1) contains point (a,-3).

What is the value of a? Show
your work.​

Answer 1

`\\ \sf\Rrightarrow y-1=(2)/(3)(x+1)`

`\\ \sf\Rrightarrow -3-1=(2)/(3)(a+1)`

`\\ \sf\Rrightarrow -4=(-2(a+1))/(3)`

`\\ \sf\Rrightarrow -2(a+1)=-4(3)`

`\\ \sf\Rrightarrow -2(a+1)=-12`

`\\ \sf\Rrightarrow a+1=(-12)/(-2)`

`\\ \sf\Rrightarrow a+1=6`

`\\ \sf\Rrightarrow a=6-1`

`\\ \sf\Rrightarrow a=5`