Question

What is the equation of a line that passes through (4, 3) and has a slope of 2?

Oy= 2x – 11
Oy=2x-1
Oy= 22 – 5
y= 22 - 7

Answer 1

Given :-

(x,y) = (4,3)

m = 2

Solution :-

We know that

y = 2x + b

3 = 2(4) + b

3 = 8 + b

3 - 8 = b

-5 = b

Now

We need to find the equation

Equation = y = 2x + b

We have

x = x

y = ?

b = -5

y = 2(x) + (-5)

y = 2(x) - 5

y = 2x - 5

Option C is exactly correct.

Answer 2

`y=2x-5`

Explanation:

Hi there!

Slope-intercept form:
`y=mx+b` where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

We're given that the slope is 2. Plug this into
`y=mx+b` as m:

`y=2x+b`

Now, to solve for the b, plug in the point (4,3):

`3=2(4)+b\\3=8+b\\3-8=b\\-5=b`

Therefore, the y-intercept is -5. Plug this back into
`y=2x+b` as b:

`y=2x+(-5)\\y=2x-5`

I hope this helps!