Question

A car traveling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of

the car (assume uniform acceleration).

Answer 1

d = 28.6 m

Explanation:

Given:

vi = 22.4 m/s

vf = 0 m/s

t = 2.55 s

Find:

d = ??

d = (vi + vf)/2 *t

d = (22.4 m/s + 0 m/s)/2 *2.55 s

d = (11.2 m/s)*2.55 s

d = 28.6 m

Answer 2

57.12 m

Explanation:

velocity= distance/time

distance= velocity×time

=22.4×2.55

=57.12 m