Determine the type and number of solutions of 4x - 4x + 1 = 0. two real solutions one real solution two imaginary solutions

Question

asked Sep 28, 2022 17.1k views

1 Answer

Bagerard · Answer 1 · 2022-10-04T23:07:14+0000

Answer:

1 real solution

Explanation:

Use discramint formula.

$b {}^(2) - 4ac$

If the discramint >0, the equation is going to have 2 real solutions

If the discramint =0, we going to have one real solution.

If the discramint<0, we going to have two imaginary solution

B is -4, A is 4 and C is 1 so

${ - 4}^(2) - 4( 4)(1) = 0$

So the equation had one real solution.