asked 71.0k views
3 votes
Find f (2b^2) for (x)=x^2-4x

Answer choice is
A. 4b^4 -8b^2
B. 2b^4-8b^2
C. -4b^2
D. 4b^2 - 8b^8

1 Answer

6 votes

Answer:

A

Explanation:

We are given the function:


f(x) = x^2 - 4x

And we want to find:


\displaystyle f(2b^2)

Substitute:


\displaystyle f(2b^2) =(2b^2)^2 -4(2b^2)

And evaluate:


\displaystyle \begin{aligned} f(2b^2) &=(2b^2)^2 -4(2b^2) \\ &=(4b^4) +(-8b^2) \\ &= 4b^4 - 8b^2 \end{aligned}

In conclusion, our answer is A.

answered
User Maulik Anand
by
7.3k points
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