N - √(c + 5 = 1) in the equation above, C is a constant. If n= 5, what is the value of c? Could you say how you got rid of the negative sign in front of the square root in the p…

Question

`n - √(c + 5 = 1)`

in the equation above, C is a constant. If n= 5, what is the value of c?

Could you say how you got rid of the negative sign in front of the square root in the process plz

​

Answer 1

c is 11

Step-by-step explanation:

`n - √(c + 5 ) = 1 \\ 5 - √(c + 5) = 1 \\`

make -√c+5 the subject:

`- √(c + 5) = 1 - 5 \\ - √(c + 5) = - 4`

divide through out by -1 :

`( - √(c + 5) )/( - 1) = ( - 4)/( - 1) \\ \\ √(c + 5) = 4`

square both sides;

`{( √(c + 5) )}^(2) = {4}^(2) \\ c + 5 = 16 \\ c = 11`

Answer 2

c=11

Step-by-step explanation:

`n - √(c + 5) = 1`

`5 - √(c + 5) = 1`

Add sqr root of c+5 to both sides

`5 = 1 + √(c + 5)`

`4 = √(c + 5)`

`16 = c + 5`

`c = 11`