Question

Number of set values of (p,q), which satisfy relation p^2 = 2q^2 ( where p and q are natural numbers )

options:
(A) 1
(B) 0
(C) 2
(D) 3

Answer 1

(B) 0

We have

`p^2 = 2q^2 \implies (p^2)/(q^2) = \left(\frac pq\right)^2 = 2`

but 2 is not a square number.