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4 votes
Electrolysis of aqueous copper(2) sulfate half ionic equation

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User Zoman
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1 Answer

3 votes

Answer:

Copper is less reactive than hydrogen, so copper (Cu) is produced at the negative electrode. The half equation is: Cu2+ + 2e- → Cu

The hydroxide ion is more reactive than the sulphate ion, therefore this forms water (H2O) and oxygen at the positive electrode.

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User Skeetastax
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