Question

The sum of the areas of two squares is 818 cm2.

The sum of the perimeters is 160cm.
Find the lengths of the sides of the squares.

Answer 1

Answer: 17 and 23 (cm)

Explanation:

Let c1 and c2 the side of thr squares.

`\left\{\begin{array}{ccc}4*c_1+4*c_2&=&160\\c_1^2+c_2^2&=&818\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}c_1+c_2&=&40\\c_1^2+(40-c_1)^2&=&818\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}c_1+c_2&=&40\\c_1^2+-40c_1+391&=&0\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}c_1&=&23\\c_2&=&17\\\end{array}\right.\ or\ \left\{\begin{array}{ccc}c_1&=&17\\c_2&=&23\\\end{array}\right.\\`