Question

If f(x)= 9^x then prove that f(m+n+p) = f(m).f(n).f(p)​

Answer 1

f(x)=9^(x)

Plugging in m+n+p=x, we have

f(m+n+p) = 9^(m+n+p)

Using the properties of exponential a^(b+c) = a^b*a^c, we have

f(m+n+p) = 9^(m)*9^(n)*9^(p)

f(m+n+p) = f(m)*f(n)*f(p)