Question

Find the equation of the line passing through the point (-7,2)(−7,2) that is perpendicular to the line 4x - 3y = 104x−3y=10.

Answer 1

Explanation:

Slope of the given line: m=4/3

Slope of the perpendiclar : m'=-3/4 (the inverse of the opposed of m)

Equation of the perpendiclar line: (passing through (-7,2))

`y-2=(x+7)*(-3)/(4) \ or\\\\ y=-(3x)/(4) -(13)/(4)`