Question

Let f(x)=r2+2 and g(x)=1–3x. Find each function value:
f(g(-1))

Answer 1

18

Explanation:

f(x)=x^2+2

g(x)=1–3x

f(g(-1))

First find g(-1) = 1-3(-1) = 1 +3 = 4

Then find f(4) = 4^2 +2 = 16+2 = 18

f(g(-1)) = 18