(3x - 2)/(7) - (5x - 8)/(4) = (1)/(14) ​

Question

`(3x - 2)/(7) - (5x - 8)/(4) = (1)/(14)`
​

Answer 1

`x=2`

Explanation:

`(3x-2)/(7)-(5x-8)/(4)=(1)/(14)`

In order to factor an integer, we need to divide it by the ascending sequence of primes 2, 3, 5.

The number of times that each prime divides the original integer becomes its exponent in the final result.

In here, Prime number 2 to the power of 2 equals 4.

`(3x-2)/(7)-(5x-8)/(2^(2) )=(1)/(14)`

First, We need to add fractions-

Rule:-

`(A)/(B) +(C)/(D) =((LCD)/(B)+(LCD)/(D)C )/(LCD)`

LCD =
`7 \cdot 2^(2)`

`(4(3x-2)+7(-(5x-8)))/(7*2^(2) ) =(1)/(14)`

`x=2`

OAmalOHopeO