Question

A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult. Assuming the acceleration is constant, how far did it travel during those 2.0 s?

Answer 1

First find Acceleration

• Initial velocity=u=0m/s
• Final velocity=v=42m/s
• Time=t=2s
• Distance=s
• Acceleration=a

`\boxed{\sf Acceleration=(v-u)/(t)}`

`\\ \sf\longmapsto Acceleration=(42-0)/(2)`

`\\ \sf\longmapsto Acceleration=(42)/(2)`

`\\ \sf\longmapsto Acceleration=21m/s^2`

Using second equation of kinematics

`\boxed{\sf s=ut+(1)/(2)at^2}`

`\\ \sf\longmapsto s=0(2)+(1)/(2)(21)(2)^2`

`\\ \sf\longmapsto s=21(2)`

`\\ \sf\longmapsto s=42m`