Question

Please help me to find this answer

Answer 1

Look in Step by Step Explanation

Explanation:

3)SOHCAHTOA

tan=opposite/adjacent

tan(20)=x/83

83tan(20)=x

x=30.209

2) SOHCAHTOA

Tangent=opposite/adjacent

Tan(62)=x/8

8tan(62)=x

x=15.04

3)SOHCAHTOA

Sin=opposite/hypotonouse

sin(25)=30/x

x=30/sin(25)

x=70.986