Question

Cos²x-√3sinxcosx = 0

Answer 1

x= п/2+пn; nE Z

x= п/6+пn; nEZ

Explanation:

(cosx)^2- √3sinxcosx=0

Factorise it

cosx(cosx-√3sinx)=0

cosx=0 or cosx=√3sinx

x= п/2+пn; nE Z cosx/cosx= √3sinx/cosx

1/√3= tgx

x= arctg 1/√3+пn; nE Z

x= п/6+пn; nEZ

The answer is x= п/2+пn; nE Z

x= п/6+пn; nEZ