Question

Using the following equation for the combustion of octane calculate the heat associated with the formation of 100.0 g of carbon dioxide. The molar mass of octane is 114.33 g/mole.

2C8H18 + 25O2 → 16 CO2 + 18 H2O

ΔH°rxn = -11018 kJ

Answer 1

The right solution is "-602.69 KJ heat".

Step-by-step explanation:

According to the question,

The 100.0 g of carbon dioxide:

=
`(100.0 \ g)/(114.33\ g/mole)`

=
`0.8747 \ moles`

We know that 16 moles of
`CO_2` formation associates with -11018 kJ of heat, then

0.8747 moles
`CO_2` formation associates with,

=
`-(0.8747)/(16)* 11018 \ KJ \ of \ heat`

=
`-0.0547* 11018`

=
`-602.69 \ KJ \ heat`