Question

Write in slope intercept form an equation of the line that passes through the given points (-3,1) (0,4)

Answer 1

`(\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{0+3}\implies \cfrac{3}{3}\implies 1`

`\begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{1}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-1=x+3\implies y=x+4`

Answer 2

y = x + 4

Explanation:

The slope

`m=(4-1)/(0+3) =(3)/(3)=1`

The equation: with point (0, 4)

`y-4=1(x-0)`

`y-4=x-0`

`y-4=x`

`y=x+4`

Hope this helps