Question

A jet airplane is in level flight. The mass of the airplane is m=8950 kg. The airplane travels at a constant speed around a circular path of radius R=9.33 mi and makes one revolution every T=0.123 h. Given that the lift force acts perpendicularly upward from the plane defined by the wings, what is the magnitude of the lift force acting on the airplane?

Answer 1

The net force is 91780.8 N.

Step-by-step explanation:

mass, m = 8950 kg

Radius, R = 9.33 miles = 15015.2 m

Time, T = 0.123 h = 442.8 s

There are two forces acting on the plane.

Horizontal force is the centripetal force and the vertical force is the weight.

`Fx =m R w^2\\\\Fx = m R (4\pi^2)/(T^2)\\\\Fx = 8950* 15015.2* (4* 3.14* 3.14)/(442.8* 442.8)\\\\Fx = 27030.8 N \\\\Fy = m g \\\\ Fy = 8950* 9.8 \\\\Fy = 87710 N`

The net force is

`F = √(Fx^2 + Fy^2)\\\\F = \sqrt {27030.8^2 + 87710^2}\\\\F = 91780.8 N`