Question

In a sequence, the first term is 6 and the common difference is 4. The thirtieth (30th) term of

this sequence is
1) 118
2) 122
3) 1261
4) 130

Answer 1

If the first term is 6, there are 29 terms left until the 30th term so you do 29 x 4 = 116 then do 6 + 116 = 122