Question

Consider a piston filled with 3 mols of an ideal gas, kept at a constant temperature 290 K. We slowly compress the gas starting at 2 m3 and ending at 1 m3. How much work do we need to do on the gas to perform this operation

Answer 1

Answer:
`-5013.65\ J`

Step-by-step explanation:

Given

No of moles
`n=3`

Temperature
`T=290\ K`

Initial volume
`V_1=2\ m^3`

Final volume
`V_2=1\ m^3`

Work done in constant temperature process is

`W=nRT\ln \left((V_2)/(V_1)\right)`

Insert the values

`\Rightarrow W=3* 8.314* 290\ln \left ((1)/(2)\right)\\\\\Rightarrow W=-870* 8.314* \ln (2)\\\Rightarrow W=-5013.65\ J`