Question

You need to make an aqueous solution of 0.182 M aluminum sulfate for an experiment in lab, using a 250 mL volumetric flask. How much solid aluminum sulfate should you add

Answer 1

Hence, 15.99 g of solid Aluminum Sulfate should be added in 250 mL of Volumetric flask.

Step-by-step explanation:

To make 0.187 M of Aluminum Sulfate solution in a 250 mL (0.250 L) Volumetric flask

The molar mass of Aluminum Sulfate = 342.15 g/mol

Using the molarity formula:-

Molarity = Number of moles/Volume of solution in a liter

Number of moles = Given weight/ molar mass

Molarity = (Given weight/ molar mass)/Volume of solution in liter

0.187 M = (Given weight/342.15 g/mol)/0.250 L

Given weight = 15.99 g