Question

(B) An airline knows from experience that the distribution of the number of suitcases that get lost each week on a certain route is normal with μ (mean) = 15.5 and σ (standard deviation) = 3.6. What is the probability that during a given week the airline will lose between 11 and 19 suitcases?

Answer 1

The correct answer is "0.7289".

Explanation:

The given values are:

Mean,

`\mu = 15.5`

Standard deviation,

`\sigma = 3.6`

As we know,

⇒
`z = ((x - \mu))/(\sigma)`

The probability will be:

⇒
`P(11< x< 19) = P((11-15.5)/(3.6) <z<(19-15.5)/(3.6))`

`=P(z< 0.9722)-P(z< -1.25)`

By using the z table, we get

`=0.8345-0.1056`

`=0.7289`