Question

Hi,there,can you solve this equation.
4x*sqrt(2x-x²)=2x-1

Answer 1

Explanation:

4x*sqrt(2x-x²)=2x-1

sqrt(2x-x²)=(2x-1)/4x

2x-x² = 4x^2 -4x + 1 /(16x^2)

32x^3 - 16x^4 = 4x^2 -4x + 1

`-16x^4+32x^3-4x^2+4x-1=0\\`

`x = 1.92887`