Question

3x + ky = 8

X – 2ky = 5
are simultaneous equations where k is a constant.
Show that x = 3.

Answer 1

3X +ky=8 eqn 1

X-2ky=5 eqn 2

but we want to eliminate ky to get our X.

So let's multiply eqn 1 by 2.

We will have 6x +2ky=16 now eqn 3

now we add eqn 1 and 2

We will have 7x=21

divide by 7

x=3