Question

Find the missing side lengths

Answer 1

`Sin \: 60=(√(3) )/(u)`

`u=√(3) /sin\:60`

`u=√(3) /√(3) /2`

`u=2`

..........................

`Cos\: 60=(v)/(2)`

`v=2\: cos\:60`

`v=2((1)/(2))`

`v=1`

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