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A.) Where does the turning point of the curve Y= 6- 4x - x^2 occur? b.) Differentiate with respect to x, (cos x)/(sin 2x)

A.) Where does the turning point of the curve Y= 6- 4x - x^2 occur? b.) Differentiate with respect to x, (cos x)/(sin 2x)
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A.) Where does the turning point of the curve Y= 6- 4x - x^2 occur?

b.) Differentiate with respect to x,
(cos x)/(sin 2x)

asked
User Jorrebor
by
8.4k points

1 Answer

5 votes

Answer:

Have you gotten the answer. if yes Hmu... Aihs I sit beside you

Explanation:

answered
User MarrLiss
by
7.2k points
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