Question

A pile of sand has been stored in the shape of a cone. Mr. Terwilliker knows that the pile is 20 feet tall and 102 feet in circumference at the base. What is the area of the conical tarpaulin needed to cover the pile?

Answer 1

400pi square feet

Explanation:

Find the radius

Find the slant height

Put it in the formula for a cone but take the circumference part out

Divide your answer by pi

The question asks for the closest answer

400pi square feet is the closest option to 418.17pi square feet.

Answer 2

The area of tarpaulin is 1315.63 ft^2.

Explanation:

height, h = 20 feet

circumference, C = 102 feet

Let the radius is r.

Circumference, C = 2 x 3.14 x r = 102

r = 16.24 feet

Let the slant height is L.

`L = √(h^2 + r^2)\\\\L = √(20^2 + 16.24^2)\\\\L = 25.8 ft`

The curved surface area is

S = 3.14 x r x L

S = 3.14 x 16.24 x 25.8 = 1315.63 ft^2