Assume that the far point of a myopic (nearsighted) eye is 5.04 m in front of the eye. A lens is used to correct the vision, such that it can focus sharply an object at infinity…

Question

asked Jun 23, 2022 79.4k views

1 Answer

Woosah · Answer 1 · 2022-06-28T19:30:35+0000

Answer:

P=-0.2D

Step-by-step explanation:

From the question we are told that:

Far-point
v=-5.04m

Where

u=-\alpha

Generally the equation for Lens is mathematically given by

(1)/(f)=(1)/(v)-(1)/(u)

$P=(1)/(-5.04)-(1)/(\alpha)$

P=-0.2D