Question

Solve the system of equations.

4x + 3y + 5z = 6
6x + 8y + 6z = 4
4x + 2y + z = 8
(x = 1, y = -1,2 = 1)
b. (x = 3, y = -3,2 = 3)
a.
C. (x = 0, y = 0, 2 = 2)
d. (x - 2, y --2, z = 0)

Answer 1

The answer is x=1 y=-1 and z=1. If you plug in the variables you get
4-3+5 and that equals 6. So that’s the answer