asked 104k views
1 vote
X+x+y+y+z+z=24

b+x+x+y+z=21

b+b+y+y=28

x+x+x+y+z=23


ASAP PLEASE
what numbers do the variables stand for

all x’s have the same numbers

all b’s have the same numbers

all y’s have the same numbers

all z’s have the same numbers

asked
User Aechlys
by
7.6k points

1 Answer

2 votes

Answer:

b = 7/2

x = 11/2

y = 21/2

z = -4

Explanation:

2x + 2y + 2z = 24

x + y + z = 12

b + 2x + y + z = 21

2b + 2y = 28

b + y = 14

3x + y + z = 23

we can start anywhere by transforming these equations in a way that always one variable is excised by others.

so, e.g.

b = 14 - y

14 - y + 2x + y + z = 21

2x + z = 7

z = 7 - 2x

3x + y + 7 - 2x = 23

x + y = 16

16 + z = 12

z = -4

-4 = 7 - 2x

-11 = -2x

11 = 2x

x = 11/2

11/2 + y = 16

y = 16 - 11/2 = 32/2 - 11/2 = 21/2

b = 14 - 21/2 = 28/2 - 21/2 = 7/2

answered
User Fahrradflucht
by
8.6k points
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