Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8. Find y. A. 16 B. 6 C. 18 D. 32

Question

asked Jan 5, 2022 107k views

1 Answer

Gsquare · Answer 1 · 2022-01-09T02:35:07+0000

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Answer:

B. 6

Explanation:

The diagonals of a parallelogram intersect at their midpoints, so ...

DE = BE

4y -8 = y +10

3y = 18 . . . . . . . add 8-y

y = 6 . . . . . . . . divide by 3

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Additional comment

The value of x is found the same way:

2x = x+2 ⇒ x = 2