Question

1 gallon = 3.8 liters 1 mile = 1.6 kilometers using the conversion above,a bus that uses that uses 10 liters of gasoline to travel 10 liters of gasoline to travel 100 kilometers would have an efficiency rating closest to a) 15 miles per gallon b) 24 miles per gallon c) 38 miles per gallon d) 60 miles per gallon

Answer 1

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Answer:

b) 24 miles per gallon

Explanation:

The usual metric measure of vehicle fuel efficiency is liters per 100 km. Greater efficiency is indicated by a lower value.

In the US, the measure is usually miles per gallon. Greater efficiency is indicated by a higher value. Since we want the efficiency expressed in miles per gallon, we need to divide distance by fuel consumption.

(distance)/(fuel used) = (100 km)/(10 L)

= (100 km)/(10 L) × (1 mi)/(1.6 km) × (3.8 L)/(1 gal) = (100×3.8)/(10×1.6) mi/gal

= 23.75 mi/gal ≈ 24 mi/gal