Question

How much heat is added if .0948g of water is increased in temperature by .728 degrees C?

.289 J

.803 J

1.46 J

.055 J

Answer 1

0.289J of heat are added

Step-by-step explanation:

We can relate the change in heat of a substance with its increasing in temperature using the equation:

q = m*ΔT*S

Where Q is change in heat

m is mass of substance (In this case, 0.0948g of water)

ΔT = 0.728°C

S is specific heat (For water, 4.184J/g°C)

Replacing:

q = 0.0948g*0.728°C*4.184J/g°C

q = 0.289J of heat are added