Question

An alloy contains 26 % of copper. What quantity of alloy is required to get 260 g of copper?​

Answer 1

Let the quantity of alloy required = m g

Then 26 % of m =260 g

`\small\bold\green{⇒}\small\bold{((26))/(100) × m = 260 g}`

`\small\bold\green{⇒}\small\bold{m = ((260 × 100))/(26) g}`

`\small\bold\green{⇒}\small\bold{m = (26000)/(26) g}`

`\small\bold\green{⇒}\small\bold{m = 1000 g}`