asked 144k views
5 votes
How many terms are in the following geometric sequence? Type your numerical answer only. Do not type any additional characters.

0.0625, 0,25, 1, 4194304

asked
User Mmilo
by
8.6k points

1 Answer

4 votes

Given:

The given geometric sequence is:

0.0625, 0.25, 1, ..., 4194304

To find:

The number of terms in the given geometric sequence.

Solution:

We have,

0.0625, 0.25, 1, ..., 4194304

Here, the first term is 0.0625 and the common ratio is:


r=(0.25)/(0.0625)


r=4

The nth term of a geometric sequence is:


a_n=ar^(n-1)

Where, a is the first term and r is the common ratio.

Putting
a_n=4194304, a=0.0625, r=4 in the above formula, we get


4194304=0.0625(4)^(n-1)


(4194304)/(0.0625)=(4)^(n-1)


67108864=(4)^(n-1)


4^(13)=(4)^(n-1)

On comparing both sides, we get


13=n-1


13+1=n


14=n

Therefore, the number of terms in the given geometric sequence is 14.

answered
User Hayk Mkrtchyan
by
7.6k points
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