asked 163k views
0 votes
The difference between the square of two numbers is 11. Twice the square of the first number increased by the square of the second number is 97 find the numbers

asked
User Fotijr
by
8.1k points

1 Answer

0 votes

Answer:

Below in bold.

Explanation:

x^2 - y^2 = 11

2x^2 + y^2 = 97

From the first equation:

y^2 = x^2 - 11

Substituting in the second equation:

2x^2 + x^2 - 11 = 97

3x^2 = 108

x^2 = 36

x = 6, -6.

Substituting for x in the first equation:

(6)^2 - y^2 = 11

y^2 = 36 - 11 = 25

y = 5, -5.

answered
User Yarco
by
7.9k points

Related questions

asked Jun 27, 2024 39.4k views
Poff asked Jun 27, 2024
by Poff
8.5k points
2 answers
1 vote
39.4k views
1 answer
4 votes
49.6k views
2 answers
2 votes
136k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.