asked 24.5k views
2 votes
How many real solutions exist for this system of equations?

y=x^2+4
y= 4x
ОА. .
zero
OB.
one
Ос.
two
OD
infinite
Reset
Next

asked
User Memento
by
8.0k points

1 Answer

4 votes

Answer:

One

Explanation:

Set each equations equal to each other


{x}^(2) + 4 = 4x


{x}^(2) - 4x + 4

Find the discrimant.


{ - 4 {}^(2) - 4(1)(4) } = 0

This means there is one real solution. Since the discramnt equal 0.

answered
User Tostao
by
8.5k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.