Question

Multiply: (2x+y) (n2-3xy+y2)

Answer 1

Hello!

(2x+y) (n2-3xy+y2)

2x* n²= 2xn²

2x* -3xy = -6x²y

2x* y² = 2xy²

y*n² = yn²

y*-3xy = -3xy²

y* y² = y³

=>

2xn²- 6x²y + 2xy² +yn²- 3xy² +y³

Answer 2

`{ \tt{(2x + y)( {n}^(2) - 3xy + {y}^(2) )}} \\ = { \tt{(2x {n}^(2) - 3 {x}^(2)y + 2x {y}^(2) + {n}^(2)y - 3x {y}^(2) + {y}^(3) )}} \\ = { \tt{ {y}^(3) - xy(y + 3x) + {n}^(2) y }}`