Register

PLEASE HELP SOON AND TRY TO EXPLAIN. Prove that if a, b, c, d are non zero real numbers, not all equal, and if a+1/b=b+1/c=c+1/d=d+1/a then |abcd|=1. Thx!

PLEASE HELP SOON AND TRY TO EXPLAIN. Prove that if a, b, c, d are non zero real numbers, not all equal, and if a+1/b=b+1/c=c+1/d=d+1/a then |abcd|=1. Thx!
asked 215k views
3 votes
PLEASE HELP SOON AND TRY TO EXPLAIN.

Prove that if a, b, c, d are non zero real numbers, not all equal, and if a+1/b=b+1/c=c+1/d=d+1/a then |abcd|=1. Thx!

asked
User John Creamer
by
8.3k points

2 Answers

4 votes
It’s possible it could be zero but it could also be one
answered
User Alpy
by
7.1k points
4 votes

Answer:

because any number over 0 is 0 and if |abcd|=1 that it is not possible to be 0

Explanation:

answered
User Tsutomu Kawamura
by
7.9k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!