Question

Please help me with this....
and show all the steps correctly...​

Answer 1

`12 (m)/(s)`

Step-by-step explanation:

• The time starts when the front of the train first gets on the bridge, and when the back end clears the bridge.
• Thus we are calculating the distance of 600 meters in 50 seconds.

`600m / 50s = 12 (m)/(s)`

Answer 2

`Given, \: Displacement, \: s \: = \: 450m \: + \: 150m \\ = \: 600m \\ Time, \: t \: = \: 50s \\ We \: know \: that, \: Velocity, v \: = \: (Displacement)/(Time) \\ = > v = (s)/(t) \\ = > v = (600m)/(50s) \\ = > v = (12m)/(s) \\ = > v = 12m {s}^( - 1)`

So, the velocity of the train is 12m/s or 12ms^(-1).