Question

Can someone please solve 3x^2+4x-7<13

Answer 1

`-(10)/(3)<x<2\:`

Explanation:

Rewrite in standard form:
`3x^2+4x-20<0`

Factor:
`\left(x-2\right)\left(3x+10\right)<0`

Solve individually for x:

`x-2<0\\x<2`

`3x+10<0\\3x<-10\\x<(-10)/(3)`

Combine:

`-(10)/(3)<x<2\:`