Answer:
0.9984 = 99.84% probability that their mean weight will be between 334 grams and 354 grams.
Explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution 
Problems of normal distributions can be solved using the z-score formula. 
In a set with mean 
 and standard deviation 
, the z-score of a measure X is given by: 
 
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X. 
Central Limit Theorem 
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean 
 and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean 
 and standard deviation 
. 
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30. 
Mean of 344 grams and a standard deviation of 10 grams.
This means that 

Sample of 10:
This means that 

What is the probability that their mean weight will be between 334 grams and 354 grams?
This is the p-value of Z when X = 354 subtracted by the p-value of Z when X = 334. 
X = 354

By the Central Limit Theorem



 has a p-value of 0.9992.
X = 334



 has a p-value of 0.0008.
0.9992 - 0.0008 = 0.9984
0.9984 = 99.84% probability that their mean weight will be between 334 grams and 354 grams.