Question

Express 34C21 as a sum of two terms from pascals triangle.

Answer 1

Given:

The combination is:

`^(34)C_(21)`

To find:

The
`^(34)C_(21)` as the sum of two terms from pascals triangle.

Solution:

According to the pascals triangle:

`^(n+1)C_(r+1)=^nC_r+^nC_(r+1)`

We have,

`^(34)C_(21)`

Using the pascals triangle formula, we get

`^(34)C_(21)=^(33)C_(20)+^(33)C_(21)`

Therefore,
`^(34)C_(21)=^(33)C_(20)+^(33)C_(21)`.