Question

When the focus and directrix are used to derive the equation of a parabola, two distances were set equal to each other. = StartRoot (x minus x) squared + (y minus (negative p)) squared EndRoot = StartRoot (x minus 0) squared + (y minus p) squared EndRoot The distance between the directrix and is set equal to the distance between the and the same point on the parabola.

Answer 1

The distance between the directrix and a point on the parabola is set equal to the distance between the focus and the same point on the parabola.

Explanation:

Hope this helps! :)

Answer 2

The answer is "A point on the parabola and Focus".

Explanation:

`= √((x - x)^2 + (y- (-p))^2) = √((x-0)^2+ (y-p)^2) \\\\= √((0)^2 + (y+p))^2) = √((x)^2+ (y-p)^2) \\\\= √((y+p))^2) = √((x)^2+ (y-p)^2) \\\\= (y+p) = (x)+ (y-p) \\\\= y+p = x+ y-p \\\\=2p=x\\\\=x=2p`

Whenever the focus and also the guideline are utilized in determining the parabolic formula, two distances have indeed been equal.

The distance from the direction, as well as a parabolic point, was equal to the distance from the center to a parabolic point.