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The equation of line a is y=-x+ 3. If line b runs perpendicular to line a and passes through (2, 6), what would be the equation of line b?

The equation of line a is y=-x+ 3. If line b runs perpendicular to line a and passes through (2, 6), what would be the equation of line b?
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The equation of line a is y=-x+ 3. If line b runs perpendicular to line a and

passes through (2, 6), what would be the equation of line b?

The equation of line a is y=-x+ 3. If line b runs perpendicular to line a and passes-example-1
asked
User ManuQiao
by
8.2k points

1 Answer

2 votes

Answer:

y = 4x -2

Explanation:

y = 4x + b

6 = 4(2) + b

6 = 8 + b

-2 = b

answered
User Elevener
by
7.7k points
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