Question

A right triangle has one leg that measures 7 inches and the hypotenuse measures 12 inches.

What is the length of the other leg?
Round your answer to the nearest hundredth.
Answer with a numeric value only. That is, do not include "in" or "inches" with your response.

Answer 1

• Hypotenuse=H=12in
• Perpendicular=P=7in
• Base=B=?

Using Pythagorean theorem

`\boxed{\sf B^2=H^2-P^2}`

`\\ \sf \longmapsto \: b = \sqrt{ {h}^(2) - {p}^(2) } \\ \\ \sf \longmapsto \: b = \sqrt{ {12}^(2) - {7}^(2) } \\ \\ \sf \longmapsto \: b = √(100 - 49) \\ \\ \sf \longmapsto \: b = √(51) \\ \\ \sf \longmapsto \: b = 7.2in`