Question

If the velocity of a body is decreased to 1/2, then K.E. of the body decreases to​

Answer 1

The Kinetic Energy is reduced to 1/4 of the original K. E.

Step-by-step explanation:

K. E. = 1/2 m v^2

If v becomes v/2 we have:

K E. = 1/2 m (v/2)^2

= 1/2 m v^2/4

So dividing the 2:

we get 1/2 m v^2/4 / 1/2 m v^2

= v^2/4 / v^2

= v^2 / 4v^2

= 1/4.

Answer 2

1/4th

Step-by-step explanation:

KE = .5mv^2

So when we decrease the velocity by half, we end up losing three fourths of net energy due to that value being squared.