Question

Does anyone know how to do this help please

Answer 1

`\boxed{\begin{array}c \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}`

Explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

`\rm\implies y = x^2+x - 6`

Here we need to substitute the different values of x , to get the different values of y.

Put x = -3 :-

`\rm\implies y = 3^2-3-6\\`

`\rm\implies y = 9 - 3 - 6 \\`

`\rm\implies y = 0`

Put x = -2 :-

`\rm\implies y = 2^2-2-6\\`

`\rm\implies y = 4 -2-6\\`

`\rm\implies y = -4`

Put x = -1 :-

`\rm\implies y = -1^2-1-6\\`

`\rm\implies y = 1 -1-6 \\`

`\rm\implies y = -6`

Put x = 1 :-

`\rm\implies y = 1^2+1-6\\`

`\rm\implies y = 2 -6`

`\rm\implies y = -4`

Put x = 2 :-

`\rm\implies y = 2^2+2-6\\`

`\rm\implies y = 4 +2-6\\`

`\rm\implies y = 2`

Put x = 3 :-

`\rm\implies y = 3^2+3-6\\`

`\rm\implies y = 9 +3-6\\`

`\rm\implies y = 6`

Final table :-

`\boxed{\begin{array}c \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}`