asked 173k views
4 votes
A CD is spinning on a CD player. In 12 radians, the cd has reached an angular speed of 17 r a d s by accelerating with a constant acceleration of 3 r a d s 2 . What was the initial angular speed of the CD

asked
User Jzbruno
by
8.3k points

1 Answer

4 votes

Answer:

The initial angular speed of the CD is equal to 14.73 rad/s.

Step-by-step explanation:

Given that,

Angular displacement,
\theta=12\ rad

Final angular speed,
\omega_f=17\ rad/s

The acceleration of the CD,
\alpha =3\ rad/s^2

We need to find the initial angular speed of the CD. Using third equation of kinematics to find it such that,


\omega_f^2=\omega_i^2+2\alpha \theta\\\\\omega_i^2=\omega_f^2-2\alpha \theta

Put all the values,


\omega_i^2=(17)^2-2* 3* 12\\\\\omega_i=√(217)\\\\\omega_i=14.73\ rad/s

So, the initial angular speed of the CD is equal to 14.73 rad/s.

answered
User Amrro
by
8.5k points
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